Reverse Engineering LEGO Architecture 21024 – The Louvre (Part 2 – The Courtyard)

This is part 2 in reverse-engineering the upcoming LEGO Architecture Louvre set #21024. (Go back and see how to build I.M Pei’s glass pyramid in Part 1.)

The plaza is easier to see in this photo from toysnbricks.com

The plaza is easier to see in this photo from toysnbricks.com

Today I wanted to build the courtyard of the Louvre set. Thankfully, I have found a few additional photos which show the building in alternate angles. I actually started off by building most of the left flank of the building, because I wanted to determine how deep the model will be. (We’ll look at it and the central part of the building in the next article.)

Aerial view of the courtyard.

Aerial view of the courtyard.

I was able to build the courtyard working from the back-left corner towards the front. The new photo made it easier to guess the sizes of the various wedge plates, which helped me arrange the grid of 2×2 tiles. (I used white tiles because I build almost everything in White.)

Annotated top-down view highlights some of the main shapes and parts.

Annotated top-down view highlights some of the main shapes and parts.

The main shapes have been highlighted as I predict the part selection. We have three 4×4 wedge plates, and at least two 3×3 wedge plates, since it is hard to tell if the 3×6 wedge is made up of two 3×3 parts or not. We can also see that position of the smaller pyramid in the back is only possible if we use a 1×2 jumper, which would be most attractively surrounded by a 2×2 corner tile, but we’ll see what they actually use.

The courtyard and the first part of the building.

The courtyard and the first part of the building.

I’m excited by a few of the parts in the set, namely Tile 1×1 (3070) and Tile 1×2 (3069) in Trans-clear. I had to substitute dark gray tiles, since I don’t actually own any 1×2 tiles in trans-clear, since it is currently a 0.20$ part in the US. There should be at least 38 of them! 1×1 clear tiles are even rarer at 0.30$ in any reasonable quantity, and I expect we will get 6 of them.

Take a look at the final section of this model in part 3, the conclusion of this exploration.

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